還是那個問題，我 eval（t）放最下面只能出來最后一組數(shù)的答案，求大神解答

抱歉我可能理解錯了意思，是希望theta1取第一個的時候其他的theta也取第一個數(shù)，theta1取第二個的時候其他的也取第二個數(shù)（一共5組變量），還是希望theta1取第一個的時候其他的theta取任意位置的數(shù)？
如果是第一種的話，
theta1 =[0,10,20,30,0];
theta2 =[0,0,0,0,10];
theta3 =[0,0,0,0,0];
theta4 =[-90,-90,-90,-90,-90];
theta5 =[0,0,0,0,0];
T=[ sin(theta1).*sin(theta5) + cos(theta2 + theta3 + theta4).*cos(theta1).*cos(theta5), cos(theta5).*sin(theta1) - cos(theta2 + theta3 + theta4).*cos(theta1).*sin(theta5), -sin(theta2 + theta3 + theta4).*cos(theta1), cos(theta1).*(120.*cos(theta2 + theta3) - 60.*sin(theta2 + theta3 + theta4) + (pi.*cos(theta2))./2)]
[ cos(theta2 + theta3 + theta4).*cos(theta5).*sin(theta1) - cos(theta1).*sin(theta5), - cos(theta1).*cos(theta5) - cos(theta2 + theta3 + theta4).*sin(theta1).*sin(theta5), -sin(theta2 + theta3 + theta4).*sin(theta1), sin(theta1).*(120.*cos(theta2 + theta3) - 60.*sin(theta2 + theta3 + theta4) + (pi.*cos(theta2))./2)]
[ -sin(theta2 + theta3 + theta4).*cos(theta5), sin(theta2 + theta3 + theta4).*sin(theta5), -cos(theta2 + theta3 + theta4), 150 - 120.*sin(theta2 + theta3) - (pi.*sin(theta2))./2 - 60.*cos(theta2 + theta3 + theta4)]
[ 0, 0, 0, 1]

輸出結果是1*20的矩陣，其中前5個數(shù)對應著變量改變時的sin(theta1).*sin(theta5) + cos(theta2 + theta3 + theta4).*cos(theta1).*cos(theta5)，其他同理